Question

1. 10g of ice at 0ºc absorbs 5460J of heat energy to melt and change to water at 50°c.
Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 kg-1 k 1​

Answer 1

Explanation:

10g of ice at 0ºc absorbs 5460J of heat energy. to melt and change to water at 50°c.

Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 kg-1 k 1..

Answer 2

The specific latent heat of fusion is 336 J/g.

Explanation:

Given that,

Mass of ice = 10 g

Heat energy = 5460 J

Change temperature = 50°C

Specific heat capacity = 4200 J/kg K

We need to calculate the specific latent heat of fusion

Using formula of heat energy

$Q=mL+mc\Delta T$

Put the value into the formula

$5460=10\times L+10\times4.2\times 50$

$L=\dfrac{5460-2100}{10}$

$L=336\ J/g$

Hence, The specific latent heat of fusion is 336 J/g.

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Topic : specific latent heat

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