1) 12, 15, 20, 35 are four numbers.
a) Determine the L.C.M. of the
numbers.
b) Determine the smallest number of
five digits which is divisible by the
above numbers.
c) What is the greatest number of four
digits which divided by the above
numbers with remainder 10 in every
time?
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Answers
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Answer:
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Step-by-step explanation:
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here is yøur answer
⭐A⭐
⭐12:12,24,36_,48,60,72,... 36 is the first number that occurs in both lists. So 36 is the LCM
⭐The multiples of 12 are : 12, 24, 36, 48, 60, 72, 84, .... The multiples of 15 are : 15, 30, 45, 60, 75, 90, .... 60 is a common multiple (a multiple of both 12 and 15), and there are no lower common multiples. Therefore, the lowest common multiple of 12 and 15 is 60.
⭐The prime factorization of 20 is: 2 x 2 x 5. The prime factorization of 25 is: 5 x 5. Eliminate the duplicate factors of the two lists, then multiply them once with the remaining factors of the lists to get lcm(20,20) = 100.
⭐And: 35=5×7. Thus, 5×7 is the prime factorization of 35. Next, you have to remember that BOTH of your factors have to go into the LCM exactly, or it won't work!
⭐B⭐
⭐The smallest number of 4-digits exactly divisible by 12, 15, 20 and 35 is 1000. 1160. 1260
⭐c⭐
30