Question

construct a triangle pqr if PQ + QR + PR is equal to 14 cm angle Q is equal to 45 degree and Angle R is equal to 60 degree write steps and justify it​

Answer 1

here's is your answer

thx

Answer 2

PR = 4.5Cm, QR = 4Cm, and PQ = 5.5Cm

Adding PR, QR, And PQ, we get,

Perimeter = 14Cm.

Also on measuring,

<P = 45.

<Q = 60.

P lies on the perpendicular bisector of XR.

Thus, XP = PR.

Q lies on the perpendicular bisector of YR.

Thus, QY = QR.

Therefore,

XP + PQ + QY = perimeter.

=> PR + PQ + QR = 14Cm.

Also,

XP = PR

=> <XRP = <PXR

<RPQ = <PXR + <PRX as exterior angle of triangle XRP.

=> <RPQ = 2<PXR

=

= 45 degree.

Same as above,

QY = QR

=> <QRY = <QYR

<PQR = <QRY + <QYR as exterior angle of triangle QRY.

=> <PQR = 2<QYR

=

= 60 degree.