Question

1.12 litre dry chlorine gas at STP was passed over a heated metal when 5.56 g of chlorine of the metal was formed. What is the equivalent weight of the metal ?

Answer 1

g is the answer to this question I think

Answer 2

Answer: 20.1 grams

Explanation:

Equivalent mass of a metal is defined as the mass which combines with 8 gram of oxygen or 35.5 grams of chlorine or 1 gram of hydrogen.

Given: Mass of metal chloride = 5.56 g

22.4 L of a gas at STP = 1mole

1.12 L of a gas at STP = $\frac{1}{22.4}\times 1.12=0.05 moles$  mass of chlorine = $moles\times {\text {molar mass}}=0.05\times 71=3.55g$

Thus mass of metal = Mass of metal chloride - mass of chlorine = ( 5.56 -3.55) g= 2.01 g

3.55 gram of chlorine combine with = 2.01 g of metal

So 35.5 gram of chlorine combines with =$\frac{2.01}{3.55}\times 35.5= 20.1g$ of metal

Thus equivalent mass of metal is 20.1 grams