1. (15 points) The mass of Earth is 5.97 x 1027 grams. In this problem, you will compare various objects to Earth’s mass.
A. The mass of a ping-pong ball is 2.3 grams. How many ping-pong balls would it take to equal the mass of Earth?
B. The mass of the moon is 7.36 • 1025 grams. To the nearest tenth, how many moons would it take to equal the mass of Earth?
C. The mass of the sun is 1.99 • 1033 grams. Use a reasonable approximation to quickly calculate how many Earths it would take to equal the mass of the sun.
Answers
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The gravitational force can be calculated with the formula: ... G= gravitational constant. M= mass of ... R= distance from earth's centre to object's centre.
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The answers are -
The answers are - (A) 3 × 10⁷ balls
The answers are - (A) 3 × 10⁷ balls (B) 81.1 moons
The answers are - (A) 3 × 10⁷ balls (B) 81.1 moons (C) 3 × 10⁵ Earths
GIVEN
Mass of the earth = 5.97 × 10²⁷ grams
Mass of ping-pong ball = 2.3 grams
Mass of the moon = 7.36 × 10²⁵ grams
Mass of the sun = 1.99 × 10³³ grams
TO FIND
(a) Number of ping pong balls
(b) Number of moon
(C) Number of Earths
SOLUTION
(A) Number of ping-pong balls
We can simply solve the above problem as follows,
Mass of Earth = 5.97 × 10²⁷ grams
Mass of 1 Ping pong ball = 2.3 grams
We can observe That,
2.3 grams = 1 pingpong ball
1 gram = 1/2.3 ping pong balls
Pingbong balls equal to the weight of Earth = 5.97 × 10²⁷ / 2.3
Dividing 5.97 by 2.3
= 2.5 × 10²⁷
Rounding the decimal to nearest whole number
= 3 × 10⁷ balls
(B) Number of moons required
Mass of the moon = 7.36 × 10²⁵ grams
We can also write it as,
7.36 × 10²⁵ grams = 1 moon
1 gram = 1/7.36 × 10²⁵ moon
So,
Number of moons that equals weight of the earth = 5.97 × 10²⁷ / 7.36 × 10²⁵
Dividing 5.97 by 7.36 and bringing 10²⁵ to the numerator by reversing the sign of exponent.
= 0.81 × 10²⁷ × 10⁻²⁵
= 0.811 × 10²
= 81.1
Hence, It will 81.1 moons
(C)
Mass of the Sun = 1.99 × 10³³ grams
Given,
Mass of the Earth = 5.97 × 10²⁷ grams
So,
Number of Earths weighing 5.97 × 10²⁷ grams = 1
Number of earths weighing 1 gram = 1/5.97 × 10²⁷ moons
Number of earth weighing 1.99 × 10³³ grams = 1.99 × 10³³ grams /5.97 × 10²⁷
Dividing 1.99 by 5.97 and bringing 10²⁷ on numerator by reversing the sign of the exponent;
= 0.33 × 10³³ × 10⁻²⁷
We know that, When base is same the exponents are added,
Therefore,
= 0.3 × 10⁶
Approximating the above number to nearest whole number
= 3 × 10⁵ Earths
Hence, The answers are -
Hence, The answers are - (A) 3 × 10⁷ balls
Hence, The answers are - (A) 3 × 10⁷ balls (B) 81.1 moons
Hence, The answers are - (A) 3 × 10⁷ balls (B) 81.1 moons (C) 3 × 10⁵ Earths
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