Question

-1/√2+(-1/√2i) find modulus and argument​

Answer 1

Step-by-step explanation:

r=|z|=√(-1/√2)²+(-1/√2)²

=1

since x lies in III quadrent

theta=-Π+alpha

tan alpha=tan Π/4

alpha=Π/4

the argument is = -Π+Π/4

=-3Π/4