1/[2(2x+3y)]+12/[7(3x-2y)] = 1/2 (eq-1)
7/(2x+3y)+4/(3x-2y) =2 (eq-2)
solve for x and y
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1
2(2x+3y)
1
+
7(3x−2y)
12
=
2
1
and
2x+3y
7
+
3x−2y
4
=2, where 2x+3y
=0 and 3x−2y
=0.
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