Math, asked by subratkumarrout05, 8 months ago

1/[2(2x+3y)]+12/[7(3x-2y)] = 1/2 (eq-1)

7/(2x+3y)+4/(3x-2y) =2 (eq-2)
solve for x and y
Please solve Guys​

Answers

Answered by devanshanand0306
1

2(2x+3y)

1

+

7(3x−2y)

12

=

2

1

and

2x+3y

7

+

3x−2y

4

=2, where 2x+3y

=0 and 3x−2y

=0.

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