(1+√2+√3)(1-√2+√3)(1+√2-√3)(-1+√2+√3)
Answers
Answered by
2
Step-by-step explanation:
√(2+√3)/(2-√3) => √(2+√3)/√(2-√3)
rationalizing the denominator
√(2+√3)(2+√3)/√(2-√3)(2+√3)
√(2+√3)²/√(2)²-(√3)²
2+√3/√(4-3) => 2+√3/√1. (√1 = 1)
=> 2+√3
since √3 =1.73.
2+√3 = 2+1.73 = 3.73 is the answer
hope this helps
Answered by
0
Answer:
(1+√2+√3)(1-√2+√3)(1+√2-√3)(-1+√2+√3)
= - (1+√2+√3)(1-√2+√3)(1+√2-√3)(1-√2-√3)
= - [ (1)² - (√2+√3)²] [ (1)² - (√2-√3)²]
= - [ 1 - { 2 + 3 + 2 (√2)(√3)}] [ 1 - { 2 + 3 - 2 (√2)(√3)}]
= - [ 1 - { 5 + 2√6}] [ 1 - { 5 - 2√6}]
= - (1)² - ( 5 + 2√6 + 5 - 2√6) + ( 5 + 2√6)( 5 - 2√6)
= - 1 - 10 + 1
= -10
HOPE THIS HELPS....
Please mark me as brainliest.....
Similar questions