Math, asked by aaditya200638, 10 months ago

(1+√2+√3)(1-√2+√3)(1+√2-√3)(-1+√2+√3)​

Answers

Answered by SohamPakrasi1
2

Step-by-step explanation:

√(2+√3)/(2-√3) => √(2+√3)/√(2-√3)

rationalizing the denominator

√(2+√3)(2+√3)/√(2-√3)(2+√3)

√(2+√3)²/√(2)²-(√3)²

2+√3/√(4-3) => 2+√3/√1. (√1 = 1)

=> 2+√3

since √3 =1.73.

2+√3 = 2+1.73 = 3.73 is the answer

hope this helps

Answered by shubhamitakarmakar
0

Answer:

(1+√2+√3)(1-√2+√3)(1+√2-√3)(-1+√2+√3)​

= - (1+√2+√3)(1-√2+√3)(1+√2-√3)(1-√2-√3)​

= - [ (1)² - (√2+√3)²] [ (1)² - (√2-√3)²]

= - [ 1 - { 2 + 3 + 2 (√2)(√3)}] [ 1 - { 2 + 3 - 2 (√2)(√3)}]

= - [ 1 - { 5 + 2√6}] [ 1 - { 5 - 2√6}]

= - (1)² - ( 5 + 2√6 + 5 - 2√6) + ( 5 + 2√6)( 5 - 2√6)

= - 1 - 10 + 1

= -10

HOPE THIS HELPS....

Please mark me as brainliest.....

Similar questions