1^2 + 3^2 + 5^2 + 21 terms = 77 * k. Find the value of k.
Answers
Answered by
0
Answer:
k = 160.23
Step-by-step explanation:
1² + 3² + 5² .... 21 terms = 77 * k
n = 21 (given)
Formula for Sum of squares of first n odd numbers = n(4n²-1)/3
=> 21[4(21)² - 1]/3
= 7(1763)
= 77(160.23)
but this is equal 77.k
=> k = 160.23
Similar questions