Math, asked by udaysinghus9339, 1 year ago

1^2 + 3^2 + 5^2 + 21 terms = 77 * k. Find the value of k.

Answers

Answered by spiderman2019
0

Answer:

k = 160.23

Step-by-step explanation:

1² + 3² + 5² .... 21 terms = 77 * k

n = 21 (given)

Formula for Sum of squares of first n odd numbers = n(4n²-1)/3

=> 21[4(21)² - 1]/3

= 7(1763)

= 77(160.23)

but this is equal 77.k

=> k = 160.23

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