Math, asked by Anonymous, 4 months ago

1.2.3.4 +2.3.4.5 +3.4.5.6 +............. find Sn of the series

Answers

Answered by shahranjit808
0

Answer:

4.5.6.7.

I hope this is helpful for you

Answered by Anonymous
17

\huge\star\underline\mathtt\blue{AnsWer}

\sf{General\:term \:=n(n+1)(n+2)(n+3)=n⁴+6n³+11n²+6n}

\rm{Sum\:of\:n\:terms=∑{n⁴}+6∑n³+11∑n²+6∑n}

\sf{=}\dfrac{n^5}{5}+\dfrac{n⁴}{2}+\dfrac{n³}{3}-\dfrac{n}{3}+</p><p>\rm{6[}\dfrac{n²(n+1)²}{4}]+

\rm{11}\dfrac{[n(n+1)(2n+1)]}{6}+

\dfrac{6[n(n+1)]}{2}

\mapsto\dfrac{n^5}{5}+2n⁴+7n³+10n²+\dfrac{9n}{2}

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