1!+2!+3!+4!.............+49! divided by 7.Find the remainder
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⇒ 1!+2!+3!+4!.............+49! divided by 7
⇒From 7! onward, these summed can be disregarded because they all contain 7 as a factor, and so their sum will result in no remainder
The sum of 5!+6! can as well because that is 120+720=840, and that is divisible by 7 as well.
⇒So need to be focused on is the sum of the first four factorials
i.e 1!+2!+3!+4! = 1+2+6+24 = 33
Thus the remainder will be 5..
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