1 +2+3+4+5+6+7..........................+100
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Answered by
1
ANSWER:
the sum of 1+2+3+4+5+6+7.........................................+100
=5050
by formulae s= n (n+1)÷2
=100 (100+1)÷2
=5050
HOPE THIS HELPS U.
the sum of 1+2+3+4+5+6+7.........................................+100
=5050
by formulae s= n (n+1)÷2
=100 (100+1)÷2
=5050
HOPE THIS HELPS U.
Answered by
0
Hey there !
1+2+3+.....+100
Sum of first n natural numbers is n(n+1)/2
Hence Sum of first 100 natural numbers =100(100+1)/2=50*101=5050
Therefore ,1 +2+3+4+5+6+7..........................+100=5050
1+2+3+.....+100
Sum of first n natural numbers is n(n+1)/2
Hence Sum of first 100 natural numbers =100(100+1)/2=50*101=5050
Therefore ,1 +2+3+4+5+6+7..........................+100=5050
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