Question

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Answer 1

x = ³√28

y = ³√27 = 3

It can also be written as,

x³ = 28

y³ = 27

Now with the equation,

$x + y - \frac{1}{x {}^{2} + xy + {y}^{2} }$

We know by identity,

x³- y³ = (x-y)(x²+xy+y²)

So, x²+xy+y² = $\frac{ {x}^{3} - {y}^{3} }{x - y}$

Putting this value in the equation we get,

=>$x + y - \frac{1}{ \frac{ {x}^{3} - {y}^{3} }{(x - y)} }$

=>$x + y - \frac{(x - y)}{ {x}^{3} - {y}^{3} }$

From given,

x³ = 28

y³ = 27

Now,

=>$x + y - \frac{(x - y)}{28 - 27}$

=>$(x + y) - \frac{(x - y)}{1}$

=>(x+y)-(x-y)

=>x+y-x+y

=>2y

=>2×3 {given}

=>6

Cheers!

Answer 2

Answer:

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