Question

1+2+3+4+5+6+7,,,,,,,,,what is he sum of 100​

Answer 1

Answer:

The sum of 100 terms is 5050.

Step-by-step explanation:

The series provided is in AP.

The sum of first n terms of an AP is:

$S_{n}=\frac{n}{2}[2a+(n-1)d]$

Given:

a = 1

d = 1

Compute the sum of first 100 terms as follows:

$S_{100}=\frac{100}{2}[(2\times1)+(100-1)(1)]\\=50\times [2+99]\\=50\times 101\\=5050$

Thus, the sum of 100 terms is 5050.

Answer 2

Sum of hundred terms= 5050

Step-by-step explanation:

In this question write values of a,n,d,

                    a= first term=1

                    d=differnce in terms of AP=1

                    n=100

By formula of sum of n terms

          Sn=n\2(2a+(n-1)d)

        sum of 100 terms= 100\2(2+(100-1)1)

                                       =50×(2+99)

                                       =50×101

         sum of 100 terms  =5050