Question

1+2+3+4+sum of first 35 natural integers is
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Answer 1

Given:

An arithmetic progression series as $1+2+3+4+....+35$

 To find:

The sum of the first $35$  natural integers

Formula to be used:

$S_{n} = \frac{n}{2} (2a + (n-1) d)$

Where,  $S_{n}$ is the sum of first  $35$ integers  

 $n$ is the number of integers

 $a$ is the first term

 $d$ is the common difference

$d$ = second term - first term = $2-1 = 1$

Step-by-step explanation:

$S_{n} = (2 + (35-1) 1)$

$S_{n} = \frac{35}{2} (2 + 34)$

$S_{n} = 35$ × $18$

$S_{n}$ = $630$

Answer:

Therefore, the sum of first  $35$ natural integers is $630$

 

Answer 2

Answer:

thaks u soo much for the answer tq