Math, asked by BanMePls, 3 months ago

1+2+3...+99999=? PLEASE I GIVE CROWN

BanMePls: LMAO I DIDNT NEED ANSWER

Answers

Answered by amkumar2005
1

Answer:

49995000

Step-by-step explanation:

GIVEN THAT

1+2+3....+99999

REQUIRED FORMULA

Sn = n/2(a+l)

where,Sn is the required sum

n = 99999

a = 1

l = 99999

So,

Sn = n/2(a+l)

Sn = 99999/2(1+99999)

Sn= 99999/2(100000)

Sn = 99999 × 5000

Sn = 499995000

so,sum of 1+2+3+4+........+99999 = 499995000

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