Math, asked by BKSs385, 10 months ago

1, 2, 3 and 4 can form 256 different four digit numbers. If digits repeated, two of them are 1111 and 1113. Then find the sum of 256 numbers.A)711040 b)711000 c)711038 d)711042

Answers

Answered by amitnrw
1

Answer:

the sum of 256 numbers = 711040

Step-by-step explanation:

1, 2, 3 and 4 can form 256 different four digit numbers. If digits repeated, two of them are 1111 and 1113. Then find the sum of 256 numbers.A)711040 b)711000 c)711038 d)711042

There are 256 Numbers

so Each Digit will appear 256 times

& each Digit will appear at each place for 256/4 = 64 times

At units place 64 times 1 , 2 , 3 & 4 appear

Sum of units place = 64 * 10 = 640

Sum of Tens place = 10 * 640 = 6400

Sum of 100's Place = 64000

Sum of 1000's place = 640000

640000 + 64000 + 6400 + 640 = 711040

the sum of 256 numbers = 711040

Similar questions