1, 2, 3 and 4 can form 256 different four digit numbers. If digits repeated, two of them are 1111 and 1113. Then find the sum of 256 numbers.A)711040 b)711000 c)711038 d)711042
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Answer:
the sum of 256 numbers = 711040
Step-by-step explanation:
1, 2, 3 and 4 can form 256 different four digit numbers. If digits repeated, two of them are 1111 and 1113. Then find the sum of 256 numbers.A)711040 b)711000 c)711038 d)711042
There are 256 Numbers
so Each Digit will appear 256 times
& each Digit will appear at each place for 256/4 = 64 times
At units place 64 times 1 , 2 , 3 & 4 appear
Sum of units place = 64 * 10 = 640
Sum of Tens place = 10 * 640 = 6400
Sum of 100's Place = 64000
Sum of 1000's place = 640000
640000 + 64000 + 6400 + 640 = 711040
the sum of 256 numbers = 711040
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