1.2/3rd of the balls in a bag are blue, the rest are pink. if 5/9th of the blue balls and 7/8th of the pink balls are defective, find the total number of balls in the bag given that the number of non defective balls is 146?
Answers
Answered by
0
let total no of balls is x
blue balls are 2x/3
pink balls are x-2x/3 = x/3
defective blue balls = 5/9*2x/3= 10x/27
defective pink balls = 7/8*x/3= 7x/24
no of non defective balls= x-10x/27-7x/23=230x/621
according to ques 230x/621= 146
x=394
blue balls are 2x/3
pink balls are x-2x/3 = x/3
defective blue balls = 5/9*2x/3= 10x/27
defective pink balls = 7/8*x/3= 7x/24
no of non defective balls= x-10x/27-7x/23=230x/621
according to ques 230x/621= 146
x=394
Similar questions