Math, asked by rlibra777, 10 months ago

1/2√5-3 rationalise the denominator

Answers

Answered by Anonymous
11

 \frac{1}{2 \sqrt{5}  - 3}  \times  \frac{2 \sqrt{5}   + 3}{2 \sqrt{5}  + 3}

 \frac{2 \sqrt{5} + 3 }{20 - 9}

 \frac{2 \sqrt{5}  + 3}{11}

please mark as branliest answer

Answered by MissKalliste
3

Answer:

\boxed{\frac {\sqrt [2]{5} + 3}{11}}

Step-by-step explanation:

\implies\large\mathtt{\frac {1}{\sqrt [2]{5} - 3}}

\implies\large\mathtt{\frac {1}{\sqrt [2]{5} - 3} \times \frac {\sqrt [2]{5} + 3}{\sqrt [2]{5} + 3}}

\implies\large\mathtt{\frac {\sqrt [2]{5} + 3}{(\sqrt [2]{5})^2 - (3)^2}}

\implies\large\mathtt{\frac {\sqrt [2]{5} + 3}{20-9}}

\implies\large\mathtt{\frac {\sqrt [2]{5} + 3}{11}}

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