Math, asked by nischaycr17, 9 months ago

1/-2√6 rationalize the denominator ​

Answers

Answered by LEGEND28480
0

Answer:

 \frac{1}{2 -  \sqrt[2]{6}  }

 \frac{1}{2 -  \sqrt[2]{6} }  \times  \frac{2 +  \sqrt[2]{6} }{2 +  \sqrt[2]{6} }

 \frac{2 +  \sqrt[2]{6} }{4 - 12}

 \frac{2  +  \sqrt[2]{6} }{ - 8}

 \frac{ - 2 -  \sqrt[2]{6} }{8}

is your answer

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