Question

(1+√2)^7+(1-√2)^7=
solve with taking C and C1​

Answer 1

Answer:

Step-by-step explanation:

(i) 2 – 3/5 = 2/1 – 3/5

                  = (2 * 5 – 3 * 1)/5                         [LCM (1, 5) = 5]

                  = (10 - 3)/5

                  = 7/5  

                  = 1              

(ii) 4 + 7/8 = 4/1 + 7/8          

                   = (4 * 8 + 7)/8                               [LCM (1, 8) = 8]

                   = (32 + 7)/8

                   = 39/8    

                   = 4        

(iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35                  [LCM (7, 5) = 35]

                        = (21 + 10)/35

                        = 31/35

(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165       [LCM (11, 15) = 165]

                            = (135 - 44)/165

                            = 91/165

(v) 7/10 + 2/5 + 3/2 = (7 * 1 + 2 * 2 + 3 * 5)/10

                                = (7 + 4 + 15)/10

Answer 2

Answer:

1^2+7^÷ is 95 Answer your question