Question

1/2{(a-b)²+(b-c)²+(a-c)²}=0 then find the relationship between a ,b and C

Answer 1

Using the algebraic relationship -

$a {}^{2} + b {}^{2} + c {}^{2} - ab - bc - ac = \frac{1}{2} (a - b) {}^{2} + (b - c) {}^{2} + (c - a) {}^{2}$
Hence , A/q

R.H.S. = 0
this implies that a = b = c

and , a² + b² + c² = ab + bc + ca respectively