1-2(a+b) -3(a+b)² factorise
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1-2(a+b) -3(a+b)²= 0
let (a+b) = s
=> 1 -2s -3s² = 0
=> 3s²+2s-1=0
=> 3s²+3s -s -1 = 0
=> 3s(s+1)-1(s+1) =0
=> (3s-1)(s+1)=0
=> s = 1/3 or s = -1
hence , a+b = 1/3 or a+b = -1
Answered by
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Here’s the answer.By the way where did y get this question?because I was solving the same one just now before seeing yr question.
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