Question

∠1=∠2 & Δ NSQ = ΔMTR then prove that Δ PTS ~ Δ PRQ

Answer 1

in triangles pst and pqr,

put q = angle 3 and r as angle 4.

so,

angle 1 = angle 3 (corresponding angles.)

angle 2 = angle 4 (corresponding angles.)

angle p is common angle

by aaa similarity,

triangle pst similar to triangle pqr.