Question

1/2(cot$\frac{b}{2}$ - tan$\frac{b}{2}$)=cot$\frac{b}{2}$

Answer 1

Answer:

$\frac{1}{2} ( \cot( \frac{x}{2} ) - \tan(\frac{x}{2}) ) = \cot(\frac{x}{2}) \\ \\ \cot( \frac{x}{2} ) - \tan(\frac{x}{2}) = 2 \cot( \frac{x}{2} ) \\ \\ \cot( \frac{x}{2} ) = - \tan( \frac{x}{2} ) \\ \\ \tan( \frac{\pi}{2} - \frac{x}{2} ) = \tan( - \frac{x}{2} ) \\ \\ \frac{\pi}{2} - \frac{x}{2} = - \frac{x}{2} \\ \\ \frac{\pi}{2} = 0$

Which is False so

No solution exists