Question

1.2 kg ice at 0°C is mixed with 1 kg water at 24°C
in a closed calorimeter. The fraction of ice that
melts is (L. = 80 cal/g)​

Answer 1

Answer:

The fraction of ice that  melts is 0.25

Explanation:

Let the amount of ice that melt is of mass "m"

now we will have

$m_1L = m_2 s \Delta T$

so we have

$m_2 = 1 kg$

$s = 1 cal/g C$

$L = 80 Cal/gm$

$\Delta T = 24^o C$

now we have

$m_1(80) = 1(1)(24)$

$m_1 = 0.3 kg$

so the fraction of ice that melt is given is

$f = \frac{0.3}{1.2}$

$f = 0.25$

#Learn

Topic : Calorimetery

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