Question

1)/(2+root 22+root 26) = 1/root a(b)2*(root a +root b-( root(a+b) ) then find the value of a and b

Answer 1

Answer:

a = 22 and b = 4

Step-by-step explanation:

Now, 1/(2 + √22 + √26)

= 1/{(√22 + 2) + √26}

= {(√22 + 2) - √26}/[{(√22 + 2) + √26)}{(√22 + 2) - √26}],

by multiplying {(√22 + 2) - √26} to both the numerator and the denominator by the conjugate of the denominator

= {(√22 + 2) - √26}/(22 + 4 + 4√22 - 26)

= {√22 + √4 - √(22 + 4)}/(4√22)

= {√22 + √4 - √(22 + 4)}/(√22 × 2²)

By the given condition,

{√22 + √4 - √(22 + 4)}/(√22 × 2²)

= {√a + √b - √(a + b)}/(√a × b²)

Comparing from both sides, we get

a = 22 and b = 4

Answer 2

Answer:

correct answer

Step-by-step explanation:

Hope it will help u

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