Math, asked by Deepak3564, 11 months ago

1/2{sinA/1+cosA+1+cosA/sinA}=1/sinA

Answers

Answered by sandy1816

1

Step-by-step explanation:

1/2[sinA/1+cosA+1+cosA/sinA]

1/2[sin²A+(1+cosA)²/sinA(1+cosA)]

1/2[sin²A+1+cos²A+2cosA/sinA(1+cosA)]

1/2[2+2cosA/sinA(1+cosA)]

1/2[2/sinA]

1/sinA

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