1/2(x-1)-2/3(x+1)=3/4
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The first thing to note here is that the solution set cannot include x=±1, since those values would make the denominators equal to zero.
Now, rearrange the equation to get the all the terms on one side
2x−1−4x+1−23=0
The common denominator here will be
3(x−1)(x+1)
which means that you must multiply the first fraction by 1=3(x+1)3(x+1), the second fraction by 1=3(x−1)3(x−1), and the third fraction by 1=(x−1)(x+1)(x−1)(x+1) to get
2x−1⋅3(x+1)3(x+1)−4x+1⋅3(x−1)3(x−1)−23⋅(x−1)(x+1)(x−1)(x+1)
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Step-by-step explanation:
1/2(x-1)-2/3(x+1)=3/4
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