Question

1/2 {(x²y²)+(x²y³)+(x³y⁴)+(x⁴y¹)}-{(x²y¹)+(x³y²)+(x⁴y³)+(x¹y⁴)} where x¹ =-5,x²=-4,x³=-1,x⁴=4 and y¹=7,y²=-5,y³=-6,y⁴=5

Answer 1

Answer:

8x−5y−3x+10y

The given expression is calculated as below

8x−5y−3x+10y=8x–3x+10y−5y

=5x+5y

Therefore, 8x−5y−3x+10y=5x+5y