Question

1,22,3,3,3,4,4,4,4,4,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4

In
the above sequence what is the number
position of 2888​

Answer 1

Answer:

1

Step-by-step explanation:

1,22,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4

In the above sequence what is the number position of 2888​

1st Sequence  = 1 + 2 + 3 + 4 = 10 Digits

2nd Sequence = 2 + 4 + 6 + 8 = 20 Digits

3rd Sequence = 3 + 6 + 9 + 12 = 30 Digits

10 + 20 + 30 +......................................

a = 10  d = 10

Sum of n Sequences > 2888

(n/2)(10 + (n-1)10) > 2888

=>5n²  > 2888

=> n > 24

For n = 24

Sum of Sequences = (24/2)(10 + 23*10) = 2880

2888 - 2880 =  8

For n = 25

1  will be 25 times  from 2881 to 3006

=>  number position of 2888​ is  1