Question

1.25g sample of limestone on heating gives 0.44g of carbon dioxide.the percentage purity of calcium carbonate in limestone is???​

Answer 1

Answer:64.8%

Explanation:

Ca(OH)2 gives CO2 and CaCO3

1.25g 0.44 (1.25-0.44=0.81) By law of conservation of mass

To find percentage of purity of calcium carbonate,

[Mass of CaCO3/mass of Ca(OH)2×100]%

(0.81/1.25×100)%

64.8%