Question

1)(27)^2/3 ÷ (81/16)^1/4
2)(36x^2)^1/2

Answer 1

1. 3^3*2/3÷(3^4*1/4)/(2^4*1/4)
= 3²÷3/2
= 9×2/3
= 6
2. (6^2*1/2)*(x^2*1/2)
= 6*x
= 6x

Answer 2

i) Given that
$\frac{(27)^ \frac{2}{3}}{ (\frac{81}{16})^ \frac{1}{4} }$

$\frac{(3^3)^ \frac{2}{3}}{ (\frac{3^4}{2^4})^ \frac{1}{4} }$

$\frac{(3^2)}{ (\frac{3}{2})}$

$\frac{9*2}{3} = 6$

ii) Given that

$(36x^2)^ \frac{1}{2}$

⇒ 6x