Question

1+2sin²Qcos2Q= sin²Q +Cos ²Q +4ksin²QCos²Q​

Answer 1

Correct option is

A

0.5

3tanθ=1

⇒tanθ=31

⇒θ=60°

∴sin2θ−cos2θ=sin2θ−cos2θ

                               =(23)2−(21)2

                               =43−41

                               =21

Hence, the answer is 0.5