1+ 2x + √1-2x
+
2
then
dy
dx
48) If y = sin-1
Answers
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0
y=sin
−1
(
1+x
2
2x
)
Differentiating above equation w.r.t. x, we have
dx
dy
=
1−(
1+x
2
2x
)
2
1
(
(1+x
2
)
2
2(1+x
2
)−2x(2x)
)
⇒
dx
dy
=
(1+x
2
)
2
−4x
2
1+x
2
(
(1+x
2
)
2
2+2x
2
−4x
2
)
⇒
dx
dy
=
(x
2
−1)
2
1
(
1+x
2
2(1−x
2
)
)
dx
dy
=
(x
2
−1)
1
(
1+x
2
2(1−x
2
)
)
dx
dy
=
1+x
2
−2
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