1)2x + 3y = 5 by elimination
3x + 4y = 6
2) x - 4y = - 4
2x + 5y = - 4
Answers
Answer:
2x + 3y = 5 by elimination
3x + 4y = 6
2) x - 4y = - 4
2x + 5y = - 4
Answer:
Question 1 )
2x + 3y = 5 ( eqn : 1 )
3x + 4y = 6 ( eqn : 2 )
⇒ ( eqn 1 × 4 ) - ( eqn 2 × 3 )
⇒ [ 4 ( 2x + 3y = 5) ] - [ 3 ( x + 4y = 6 ) ]
⇒ ( 8x + 12y = 20 ) - ( 3x + 12y = 18
Using Elimination method
8x + 12y = 20
- 9x + 12y = 18
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-x + 0 = 2
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⇒ - x = 2
x = -2
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Question 2 )
x - 4y = -4 ( eqn : 1 )
2x + 5y = -4 ( eqn : 2 )
⇒ ( eqn 1 × 5 ) - ( eqn 2 × - 4 )
⇒ [ 5( x - 4y = - 4) ] - [ -4( 2x + 5y = - 4 ) ]
⇒ ( 5x - 20y = -20 ) - ( -8x - 20y = +16 )
Using Elimination Method
5x - 20y = -20
- -8x - 20y = +16
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13x + 0 = 36
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⇒ 13x = 36
x =