(1) ׳-2ײ-×+2
(2) ׳-3ײ-9×-5
(3) 2y³+y²-2y-1
(4) ׳+13ײ+32×+20
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Answer:
2y³+y²-2y-1
= Y²(2y+1)-1(2y+1)
=(2y+1) (y²-1)
= (2y+1) (y+1) (y-1)
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