(√6/√2+√3) + (3/√6+√3) - (4√3/√6+√2)
Answers
Answered by
1
Answer:
mark me as brainliest
Step-by-step explanation:
= ( u.r6 / u. r2 + u. r 3 ) + ( 3/ u. r6 + u. r 3 ) -(4 u. r3 /u. r 6 +u. r 2 )
= ( 3 + u. r. 3 ) + ( 1/ u. r 2 + u. r 3 ) -( 2+ u. r 3 )
= 3+ u. r. 3 + 1/ u. r 2 + u. r 3 - 2 + u. r. 3
= 3 -2 + u. r 3 + 1/ u. r 2 + u. r 3 + u. r 3
= 1 + 9 u. r + 1/ u. r 2
= 1 + 18 u. r / u. r + 1/ u. r 2
= 1+ 19 u. r /2 u. r
u. r refers to the underroot
Answered by
10
Answer:
♥️♥️ follow me ♥️♥️
=2\sqrt{3}+\sqrt{6}+3\. ( Because, √18 = √(9×2) = √9 × √2 = 3√2 and √12 = √(4×3) = √4 × √3 = 2√3 ). =0. 4.7.
♥️♥️ please mark me as brainliest♥️♥️
Similar questions