Question

1÷√3+√2-2÷√5-√3-3÷√2-√5

Answer 1

Solution:-

$\frac{1}{ \sqrt{3} } + \sqrt{2} - \frac{2}{ \sqrt{5} } - \sqrt{3} - \frac{3}{ \sqrt{2} } - \sqrt{5} \\ \frac{ \sqrt{10} + \sqrt{60} - 2 \sqrt{6} - \sqrt{90} - 3 \sqrt{15} - \sqrt{150} }{ \sqrt{30} } \\ \frac{ \sqrt{10} + 2 \sqrt{15} - 2 \sqrt{6} - 3 \sqrt{10} - 5 \sqrt{6} }{ \sqrt{30} } \\ \frac{ - 2 \sqrt{10} - 7 \sqrt{6} + 2 \sqrt{15} }{ \sqrt{30} }$

Answer 2

Heya !


Here is yr answer
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$= > \frac{1}{ \sqrt{3} + \sqrt{2} } - \frac{2}{ \sqrt{5} - \sqrt{3} } - \frac{3}{ \sqrt{2} - \sqrt{5} } \\ \\ = > \frac{1}{ \sqrt{ 3 } + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } - \frac{2}{ \sqrt{ 5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } - \frac{3}{ \sqrt{2} - \sqrt{5} } \times \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\ \\ = > \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} - \frac{2 \sqrt{5} + 2 \sqrt{3} }{5 - 3} - \frac{3 \sqrt{2} + 3 \sqrt{3} }{2 - 5} \\ \\ = > \frac{ \sqrt{3} - \sqrt{2} }{1} - \frac{ 2\sqrt{5} + 2 \sqrt{3} }{2} - \frac{3 \sqrt{2} + 3 \sqrt{3} }{ - 3} \\ \\ = > \sqrt{3} - \sqrt{2} - \frac{2( \sqrt{5} + \sqrt{3} )}{2} - \frac{3( \sqrt{2} + \sqrt{3} )}{ - 3} \\ \\ = > \sqrt{3} - \sqrt{2} - \sqrt{5} - \sqrt{3} - \sqrt{2} - \sqrt{3} \\ \\ = > - 2 \sqrt{2} - \sqrt{5} - \sqrt{3}$


Hope it hlpz.....