Question

-1 , -3/2 , -2 ,..... are these terms in ap ? justify

Answer 1

Answer:

if they are in a.p d must be same

d1= -3/2+1 = -1/2

d2= -2+3/2 = -1/2

d1=d2

so, they are in ap

Answer 2

$\huge\mathfrak\purple{answer}$

$-1, \frac {-3}{2} , -2,..............$

first digit =a , common difference =d

if they are in Ap then d is same.

$d1=- \frac{3}{2} - ( - 1)$

$= - \frac{3}{2} + 1 = \frac{ - 3 + 2}{2}$

$= \frac{ - 1}{2}$

$d2=- 2 - ( \frac{ - 3}{2} )$

$= - 2 + \frac{3}{2} = \frac{ - 4 + 3}{2}$

$- \frac{1}{2}$

°•° common difference is same d1=d2

•°• they are in ap

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