Question

(1^3+2^3+3^3)^1/2

Please answer the question with all the steps

Answer 1

 = ( 1^3 + 2^3 + 3^3 )^(1/2 )

[ ( 1^3 = 1 x 1 x 1 = 1 ) , ( 2^3 = 2 x 2 x 2 = 8 ) , ( 3^3 = 3 x 3 x 3 = 27 ) ]

 = ( 1 + 8 + 27 )^( 1/2 )

 = ( 36 ) ^ ( 1/2 )

  Using identity , [ a^(1/2 ) = √a ]

 = √36

 = 6

Answer 2

Heya !


Here is yr answer
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=> (1^3+2^3+3^3)^1/2

=> (1+8+27)^1/2

=> (36)^1/2

=> (6^2)^1/2

=> (6)^2*1/2

=> 6^1

=> 6



Hope it hlpz....