Math, asked by jazam, 1 year ago

integrate
2y -  \sqrt{ {r}^{2}    -  {y}^{2} }

Answers

Answered by avinash0564
1

y {}^{2}  -  y \div 2 |x +   \sqrt{r { }^{2}  -  y {}^{2} }  |  + {r {}^{2} \div 2} {sin {}^{ - 1}y \div r }
the above is your answer
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