Question

1^3+2^3+3^3......+40^3 is​

Answer 1

Answer:

672400

Step-by-step explanation:

${1}^{3} + {2}^{3} + {3}^{3} + {4}^{3} + ...... + {n}^{3} = \frac{ {n}^{2} {(n + 1)}^{2} }{4} \\ \\ given \\ \\ n \: = 40 \\ \\ {1}^{3} + {2}^{3} + {3}^{3} + {4}^{3} + ...... + {40}^{3} = \frac{ {40}^{2} \times {41}^{2} }{4} \\ \\ = 672400$

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Answer 2

Answer:

672400

Step-by-step explanation:

$\begin{lgathered}{1}^{3} + {2}^{3} + {3}^{3} + {4}^{3} + ...... + {n}^{3} = \frac{ {n}^{2} {(n + 1)}^{2} }{4} \\ \\ given \\ \\ n \: = 40 \\ \\ {1}^{3} + {2}^{3} + {3}^{3} + {4}^{3} + ...... + {40}^{3} = \frac{ {40}^{2} \times {41}^{2} }{4} \\ \\ = 672400\end{lgathered}$