1^3_2^3+3^3_....+9^3 the sum of the series
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its the summation of cube
((n)(n+1)/2)²
((9*10)/2)²
45²=2025
((n)(n+1)/2)²
((9*10)/2)²
45²=2025
raghunathk8pc0mfq:
thanks but is wrong
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Given,
1³ + 2³ +3³ ..............9³
The sum following series is given by formula
Putting n= 9
We get,
→{9²(9+1)²}/2²
→ {81*10²}/4
→ {81*100}/4
→81*25
→2025
1³ + 2³ +3³ ..............9³
The sum following series is given by formula
Putting n= 9
We get,
→{9²(9+1)²}/2²
→ {81*10²}/4
→ {81*100}/4
→81*25
→2025
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