Question

1/3(3x-2)+1/4(4x+3)=0

Answer 1

$\frac{1}{3} (3x - 2) + \frac{1}{4} (4x + 3) = 0 \\ \frac{3}{3} x - \frac{2}{3} + \frac{4}{4} x + \frac{3}{4} = 0 \\ x - \frac{2}{3} + x + \frac{3}{4} = 0 \\ 2x - \frac{2}{3} + \frac{3}{4} = 0 \\ 2x = \frac{2}{3} - \frac{3}{4} \\ 2x = \frac{8 - 9}{12} \\ x = - \frac{1}{12} \times \frac{1}{2} \\ x = - \frac{1}{24}$

Answer 2

$\frac{1}{3} (3x - 2) + \frac{1}{4} (4x + 3) = 0$