1+3+5+7+.....+35 find the sum of value
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Answer:
a=1
d=5-3
=2
n=?
tn=35
tn=a+(n-1)d
35=1+(n-1)2
35-1=2n-2
34=2n-2
34+2=2n
36=2n
36÷2=n
18=n
n=18
therefore,
Sn=n/2[2a+(n-1)d]
Sn=18/2[2.1+(18-1)2]
Sn=9[2+(17)2]
Sn=9[2+34]
Sn=9×36
Sn=324
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