Question

(1+3+5+7+...........+3983) / 1992 is equal to

Answer 1

Answer:

1992

Step-by-step explanation:

Tn=3983 a=1 d=2

Tn=a+(n-1)d

3983=1+(n-1)2

3982=(n-1)2

n-1=3982/2

n-1=1991

n=1992

to find the sum of all the numbers:

S=n/2[2a+(n-1)d]

S=1992/2[2x1+(1992-1)2]

S=996[2+(1991x2)]

S=996[2+3982]

S=996x 3984

S=3968064

now the sum didvided by the number given:

3968064/1992=1992

therefore, the answer is 1992

hope that helped

mark as brainliest... plz

this took a long time

Answer 2

Answer:

1992

Step-by-step explanation:

Equation: (1+3+5+7+......+3983)/1992

As 1 3 5 7..... 3983 are in AP series.

Therefore ,Sum of AP series = (first term +last term) * number of terms/2

Number of terms= no of odd numbers from 1 to 3983

ie: 1992 (half of total numbers)

=>Sum=(1+3983)*1992/2

=>1992*1992

Then puting this in above equation-

(1992*1992)/1992

=> 1992 ANS