Question

1.3.5.7.9.........(2n-1) is.......

Answer 1

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Here's your answer...

$1 \times 3 \times 5 \times 7.....(2n - 1) \\ = \frac{1 \times 2 \times 3 \times 4....2n}{2 \times (1 \times 2 \times 3...n)} \\ = \frac{(2n)! }{2 \times n! }$

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