Question

1/√3+√6 ... rationalise the denominator

Answer 1

Answer:

1/√3+√6× √3-√6/√3-√6

√3-√6/3-6

√3-√6/-3

Is your answer.

Hope it helps.

Answer 2

Answer:

Step-by-step explanation:

Given -- 1/√3+√6

So to rationalise the denominator we need to change the sign of the denominator that is --

√3+√6 => √3 -√6

So now we need to multiply that is --

1. × √3 -√6. √3 -√6

____. _____ = ________

√3+√6. × √3 -√6 (√3+√6.) -(√3 -√6.)

Here in the denominator we used an identity that is (a square - b square )

So out equation will be ---

√3 -√6 / √3 square- √6 square

√3 -√6/ 3-6

√3 -√6/ -3

Hence this is ur answer....