Question

1+3 cosec2 Rita .cot2 tita +1cot6 tita =1÷sin 6 tita
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Answer 1

Answer:

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Answer 2

I am using A in ace of thita

1 + 3 cosec^2 A cot^2 A + cot^6 A

1 + 3cos^2 A/ sin^4 A + cos^6 A/ sin^6 A

(sin^6 A + 3 sin^2 A cos ^2 A + cos^6 A)/ sin^6 A

((sin2A)^3 + (cos^2 A)^3 + 3 sin^2 A cos^2 A)/sin^6A

((sin^2 A + cos^2 A)^3 - 3 sin^2 A cos^2 A(sin^2 A + cos^2 A) - 3 sin^2 A cos^2 A) / sin^6 A

(1 - 3 sin^2 A cos^2 A + 3 sin^2 A cos^2 A) / sin^6 A

1 / sin^6 A

RHS proved